(i)[3]
Show that $I = 8e - 2$.
(ii)[2]
Draw the curve $y = 4e^{\frac{1}{2}x} + 3$ for $0 \leq x \leq 2$.
(iii)[1]
State whether an estimate of $I$ found by the trapezium rule will be more than or less than $8e - 2$. Justify your response.
Mathematics 9709 · AS & A Level · Integration
Integration — practice question
The definite integral $I$ is given by $I = \int_0^2 (4e^{\frac{1}{2}x} + 3) \, dx$.