(a)[1]
Express $\cos^2 x$ using $\cos 2x$.
(b)[5]
Hence establish that $\int_0^{\frac{\pi}{6}} (\cos^2 x + \sin 2x)\,dx = \frac{1}{8}\sqrt{3} + \frac{1}{12}\pi + \frac{1}{4}$.
Mathematics 9709 · AS & A Level · Integration
Express $\cos^2 x$ using $\cos 2x$.
Hence establish that $\int_0^{\frac{\pi}{6}} (\cos^2 x + \sin 2x)\,dx = \frac{1}{8}\sqrt{3} + \frac{1}{12}\pi + \frac{1}{4}$.
This 6-mark question has a full step-by-step worked solution and mark scheme. One marking point: “State the correct expression $\frac{1}{2} + \frac{1}{2} \cos 2x$, or an equivalent result” …