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Show that the value of $\int_0^1 (e^x + 1)^2 \, dx$ is $\frac{1}{2}e^2 + 2e - \frac{3}{2}$.
Mathematics 9709 · AS & A Level · Integration
Mathematics 9709 · AS & A Level · Integration
Show that the value of $\int_0^1 (e^x + 1)^2 \, dx$ is $\frac{1}{2}e^2 + 2e - \frac{3}{2}$.