The diagram depicts the curve with equation $y = 8\mathrm{e}^{-x} - \mathrm{e}^{2x}$. This curve meets the $y$-axis at $A$ and the $x$-axis at $B$. The shaded area lies between the curve and the two coordinate axes.
(a)[3]
Determine the gradient of the curve at $A$.
(b)[5]
Show that the $x$-coordinate of $B$ is $\ln 2$ and then find the area of the shaded region.
Worked solution & mark scheme
This 8-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Differentiate to get $k_1e^{-x}+k_2e^{2x}$” …