(a)[2]
Prove that $\frac{1 - \cos 2\theta}{1 + \cos 2\theta} \equiv \tan^2 \theta$ holds.
(b)[4]
Hence determine the exact value of $\int_{\pi/6}^{3\pi/4} \frac{1 - \cos 2\theta}{1 + \cos 2\theta} \, d\theta$.
Mathematics 9709 · AS & A Level · Integration
Prove that $\frac{1 - \cos 2\theta}{1 + \cos 2\theta} \equiv \tan^2 \theta$ holds.
Hence determine the exact value of $\int_{\pi/6}^{3\pi/4} \frac{1 - \cos 2\theta}{1 + \cos 2\theta} \, d\theta$.
This 6-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Apply the correct double-angle formula, or carry out $t$-substitution twice” …