The diagram presents a section of the curve $y = \frac{8}{\sqrt{3x + 4}}$. It crosses the $y$-axis at $A(0,4)$. The normal drawn to the curve at $A$ meets the line $x = 4$ at $B$.
(i)[5]
Find the coordinates of point $B$.
(ii)[6]
Show, with all necessary working, that the areas of regions $P$ and $Q$ are equal.
Worked solution & mark scheme
This 11-mark question has a full step-by-step worked solution and mark scheme. One marking point: “So, $\dfrac{dy}{dx}=-\dfrac{12}{(3x+4)^{3/2}}$” …