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By rewriting $\frac{4x^2 + 5x + 3}{2x^2 + 5x + 2}$ as a partial fractions expansion first, prove that $\int_0^4 \frac{4x^2 + 5x + 3}{2x^2 + 5x + 2}\,dx = 8 - \ln 9$.
Mathematics 9709 · AS & A Level · Integration
By rewriting $\frac{4x^2 + 5x + 3}{2x^2 + 5x + 2}$ as a partial fractions expansion first, prove that $\int_0^4 \frac{4x^2 + 5x + 3}{2x^2 + 5x + 2}\,dx = 8 - \ln 9$.
This 10-mark question has a full step-by-step worked solution and mark scheme. One marking point: “State or indicate the form $A+\frac{B}{2x+1}+\frac{C}{x+2}$” …