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Find $g^{-1}(x)$ and hence verify that, if $a=6$, then $g^{-1}(x)=g(x)$.
Mathematics 9709 · AS & A Level · Functions
Functions — practice question
For $x>\frac{3}{a}$, the function $g$ is defined by $g(x)=\frac{2}{ax-3}+\frac{1}{2}$, where $a$ is a positive constant.
Worked solution & mark scheme
This 4-mark question has a full step-by-step worked solution and mark scheme. One marking point: “From $y=\frac{2}{ax-3}+\frac12$, it follows that $(y-\frac12)(ax-3)=2$” …
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