(a)[4]
Show that $\frac{dy}{dx}=\frac{x^2+2xy}{2y^2-x^2}$.
(b)[4]
Hence determine the coordinates of the points on the curve where the normal is parallel to the $y$-axis.
Mathematics 9709 · AS & A Level · Differentiation
Show that $\frac{dy}{dx}=\frac{x^2+2xy}{2y^2-x^2}$.
Hence determine the coordinates of the points on the curve where the normal is parallel to the $y$-axis.
This 8-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Recognise or state $6y^2\frac{dy}{dx}$ as the derivative of $2y^3$” …