The curve is defined by $y=\frac{8}{3x-8}-\frac{6}{x-1}$.
(a)[6]
Find the coordinates of the point where the tangent at $(3,5)$ meets the line $y=-8x$.
(b(i))[3]
Find the $x$-coordinates of the stationary points of the curve.
(b(ii))[4]
Find $\frac{d^2y}{dx^2}$ and hence determine the nature of each stationary point.
Worked solution & mark scheme
This 13-mark question has a full step-by-step worked solution and mark scheme. One marking point: “$\frac{dy}{dx}=\frac{-24}{(3x-8)^2}+\frac{6}{(x-1)^2}$” …