(a)[3]
Demonstrate that $\dfrac{dy}{dx} = \dfrac{-3x^2 + 6x}{2y + 3}$.
(b)[5]
Hence determine the coordinates of the points on the curve where the tangent is parallel to the $x$-axis.
Mathematics 9709 · AS & A Level · Differentiation
Differentiation — practice question
A curve is defined by $x^3 + y^2 + 3x^2 + 3y = 4$.
Worked solution & mark scheme
This 8-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Differentiate $y^2$ correctly to obtain $2y\frac{dy}{dx}$.” …
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