Mathematics 9709 · AS & A Level · Differentiation

Differentiation — practice question

A curve is described by the parametric equations $x = (\ln t)^2$ and $y = e^{2 - t^2}$, where $t > 0$.

(main)[4]

Find the gradient of the curve at the point for which $t = e$, simplifying your answer.

Worked solution & mark scheme

This 4-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Show that $\dfrac{dx}{dt}=\dfrac{2}{t}\ln t$.” …