Mathematics 9709 · AS & A Level · Differentiation

Differentiation — practice question

The curve is given in parametric form by $x = \sqrt{t} + 3$ and $y = \ln t$, with $t > 0$.
(a)[3]

Find a simplified formula for $\frac{dy}{dx}$ in terms of $t$.

(b)[3]

Hence determine the exact coordinates of the point on the curve where the gradient of the normal is $-2$.

Worked solution & mark scheme

This 6-mark question has a full step-by-step worked solution and mark scheme. One marking point: State the correct derivative of $x$ or $y$ with respect to $t$.

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