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Show that, therefore, $\frac{dy}{dx} = \cot t$.
Mathematics 9709 · AS & A Level · Differentiation
Differentiation — practice question
For this curve, the parametric equations are $x = 2t - \tan t$, $y = \ln(\sin 2t)$, with $0 < t < \frac{1}{2}\pi$.
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This 5-mark question has a full step-by-step worked solution and mark scheme. One marking point: “State or indicate $\frac{dx}{dt}=2-\sec^22t$ or $\frac{dy}{dt}=\frac{2\cos2t}{\sin2t}$” …
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