In a large industrial water tank, if the water depth is x metres, then the water volume V \text{ m}^3 in the tank is given by $V = 243 - \frac{1}{3}(9 - x)^3$. The tank is being filled at a steady rate of $3.6\text{ m}^3$ per hour.
(main)[5]
Determine the rate at which the water depth is increasing when the depth is $4\text{ m}$, and give your answer in $\text{cm}$ per minute.
Worked solution & mark scheme
This 5-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Differentiation gives $\frac{dv}{dx}=(9-x)^2$” …