(a)[4]
Show that $\frac{dy}{dx}=\frac{2y e^x-y^2}{2y-e^x}$.
(b)[4]
Determine the exact coordinates of the point on the curve at which the tangent is parallel to the $y$-axis.
Mathematics 9709 · AS & A Level · Differentiation
Differentiation — practice question
A curve has equation $y e^{2x} - y^2 e^x = 2$.