Mathematics 9709 · AS & A Level · Differentiation

Differentiation — practice question

The sketch shows the curve with parametric equations $x = \ln(2t + 3)$ and $y = \dfrac{2t - 3}{2t + 3}$. The curve meets the $y$-axis at the point $A$ and meets the $x$-axis at the point $B$.
(a)[4]

Show that $\dfrac{dy}{dx} = \dfrac{6}{2t + 3}$.

(b)[2]

Find the gradient of the curve at $A$.

(c)[2]

Find the gradient of the curve at $B$.

Worked solution & mark scheme

This 8-mark question has a full step-by-step worked solution and mark scheme. One marking point: Obtain $\dfrac{dx}{dt}=\dfrac{2}{2t+3}$

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