(a)[4]
Show that $\frac{dy}{dx} = \frac{4e^{2x}y}{3y^2 - 2e^{2x}}.$
(b)[3]
The curve goes through the point $(0, 2)$. Find the equation of the tangent to the curve at this point, giving your answer in the form $ax + by + c = 0.$
(c)[2]
Show that the curve has no stationary points.