The parametric equations for a curve are $x = 2e^{2t} + 4e^{t}$ and $y = 5te^{2t}$.
(i)[6]
Determine $\frac{dy}{dx}$ in terms of $t$ and hence give the coordinates of the stationary point, with each coordinate correct to $2$ decimal places.
(ii)[3]
Determine the gradient of the normal to the curve at the point where it crosses the $x$-axis.
Worked solution & mark scheme
This 9-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Derive $\dfrac{dx}{dt}=4e^{2t}+4e^t$” …
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