Mathematics 9709 · AS & A Level · Differentiation

Differentiation — practice question

The parametric form of a curve is $x = (t+1)e^t$, $y = 6\sqrt{t+4}$.
(main)[6]

Determine the equation of the tangent to the curve when $t = 0$, and give your answer in the form $ax + by + c = 0$ where $a$, $b$ and $c$ are integers.

Worked solution & mark scheme

This 6-mark question has a full step-by-step worked solution and mark scheme. One marking point: Derive $\dfrac{dx}{dt}=e^t+(t+1)e^t$ or an equivalent expression

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