Mathematics 9709 · AS & A Level · Differentiation

Differentiation — practice question

The diagram depicts the curve whose parametric equations are $x = 3\cos t$, $y = 2\cos\left(t - \frac{1}{6}\pi\right)$, for $0 \leq t < 2\pi$.
(i)[5]

Show that $\frac{dy}{dx}$ is equal to $\frac{1}{3}(\sqrt{3} - \cot t)$.

(ii)[4]

Find the equation of the tangent at the point where the curve meets the positive $y$-axis, and present your answer in the form $y = mx + c$.

Worked solution & mark scheme

This 9-mark question has a full step-by-step worked solution and mark scheme. One marking point: Differentiate to obtain $\dfrac{dx}{dt}=-3\sin t$

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