Mathematics 9709 · AS & A Level · Differentiation

Differentiation — practice question

A curve is described parametrically by $x = 1 + \sqrt{t}$ and $y = 3 \ln t$.
(i)[5]

Find the exact gradient of the curve at point $P$ when $y = 6$.

(ii)[3]

Show that the tangent to the curve at $P$ passes through the point $(1, 0)$.

Worked solution & mark scheme

This 8-mark question has a full step-by-step worked solution and mark scheme. One marking point: State $\dfrac{dx}{dt}=\tfrac12 t^{-\tfrac12}$ or $\dfrac{dy}{dt}=\dfrac3t$

  • Full mark scheme, point by point
  • Step-by-step worked solution
  • Write your answer & get it marked instantly by AI