(i)[4]
Express $\frac{dy}{dx}$ in terms of $t$, and simplify the result.
(ii)[2]
Find the gradient of the curve at the point where $x=1$.
Mathematics 9709 · AS & A Level · Differentiation
Differentiation — practice question
The parametric equations describing a curve are $x=\frac{4t}{2t+3}$, $y=2\ln(2t+3)$.
Worked solution & mark scheme
This 6-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Apply the quotient rule, or an equivalent method, to get $\dfrac{dx}{dt}=\dfrac{4(2t+3)-8t}{(2t+3)^2}$ or an equivalent result” …
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