The diagram gives the garden's dimensions in metres, and the garden is L-shaped. Its perimeter is $48\text{ m}$.
(i)[1]
Find a formula for $y$ in terms of $x$.
(ii)[2]
Given that the garden's area is $A\text{ m}^2$, show that $A = 48x - 8x^2$.
(iii)[4]
As $x$ is allowed to vary, find the greatest possible area of the garden, and show that this is a maximum value rather than a minimum value.
Worked solution & mark scheme
This 7-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Correct result: $y=\dfrac{1}{6(48-8x)}$” …
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