(i)[4]
Show that the tangent at the point $(-2, 2)$ is parallel to the $x$-axis.
(ii)[5]
Find the equation of the tangent to the curve at the other point on the curve for which $x = -2$, and give your answer in the form $y = mx + c$.
Mathematics 9709 · AS & A Level · Differentiation
Differentiation — practice question
The curve is defined by the equation $x^2 + 2xy - y^2 + 8 = 0$.
Worked solution & mark scheme
This 9-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Give $2y\frac{dy}{dx}$ as the derivative of $y^2$, or an equivalent expression” …
- Full mark scheme, point by point
- Step-by-step worked solution
- Write your answer & get it marked instantly by AI