(a)[3]
Show that no point on the curve has $y$-coordinate $e^{-1}$.
(b)[6]
Find the equation of the tangent to the curve at the point $(2, e^2)$. Give your answer in the form $y = mx + c$, with $m$ and $c$ exact constants.
Mathematics 9709 · AS & A Level · Differentiation
Differentiation — practice question
The curve is defined by $(x^2 - 3)\ln y + 6x = 14$.
Worked solution & mark scheme
This 9-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Replace $y=e^{-1}$ and reduce to a quadratic equation in $x$” …
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