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Find the equation of the normal to the curve at the point for which $t = \frac{1}{6}\pi$. Give your answer in the form $ax + by + c = 0$ where $a$, $b$ and $c$ are integers.
Mathematics 9709 · AS & A Level · Differentiation
Differentiation — practice question
The curve has the parametric equations $x = 4\cos^2 t$, $y = \sqrt{3}\sin 2t$, for values of $t$ satisfying $0 < t < \frac{1}{2}\pi$.
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