(a)[4]
Show that the result is $\frac{dy}{dx} = \frac{2xy}{2ay - x^2}$.
(b)[4]
Hence determine the coordinates of the points at which the tangent to the curve is parallel to the $y$-axis.
Mathematics 9709 · AS & A Level · Differentiation
Differentiation — practice question
The curve is given by $x^2y - ay^2 = 4a^3$, where $a$ is a constant that is not zero.
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This 8-mark question has a full step-by-step worked solution and mark scheme. One marking point: “State or imply $2xy+x^2\frac{dy}{dx}$ as the differentiated form of $x^2y$.” …
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