Mathematics 9709 · AS & A Level · Differentiation

Differentiation — practice question

Water enters a tank at a steady rate of $500\,\text{cm}^3$ per second. The water depth in the tank is $h$ cm, measured $t$ seconds after filling begins. When the water depth is $h$ cm, the volume, $V\,\text{cm}^3$, of water in the tank is given by the formula $V = \dfrac{4}{3}(25 + h)^3 - \dfrac{62500}{3}$.
(a)[3]

Find the rate at which $h$ is increasing at the instant when $h = 10\,\text{cm}$.

(b)[3]

At a different instant, the rate at which $h$ is increasing is $0.075\,\text{cm}$ per second. Find the value of $V$ at this instant.

Worked solution & mark scheme

This 6-mark question has a full step-by-step worked solution and mark scheme. One marking point: Differentiate the volume formula correctly with respect to $h$

  • Full mark scheme, point by point
  • Step-by-step worked solution
  • Write your answer & get it marked instantly by AI