(a)[5]
Show that the derivative is $\frac{dy}{dx} = \frac{\cos t}{\sin^{2} t}$.
(b)[3]
Find the equation of the tangent to the curve at the point for which $y = 0$.
Mathematics 9709 · AS & A Level · Differentiation
Differentiation — practice question
A curve is described parametrically by $x = \frac{1}{\cos t}$ and $y = \ln \tan t$, where $0 < t < \frac{1}{2}\pi$.