Mathematics 9709 · AS & A Level · Differentiation

Differentiation — practice question

The curve is defined parametrically by $x = e^t - 2e^{-t}$ and $y = 3e^{2t} + 1$.
(main)[5]

Find the equation of the tangent to the curve when $t = 0$.

Worked solution & mark scheme

This 5-mark question has a full step-by-step worked solution and mark scheme. One marking point: State $\frac{dx}{dt}=e^t+2e^{-t}$ and $\frac{dy}{dt}=6e^{2t}$

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