(i)[4]
Show that $\frac{dy}{dx} = \frac{2x^2 - y^2}{y^2 + 2xy}$.
(ii)[5]
Find the coordinates of the two points on the curve where the tangent is parallel to the $y$-axis.
Mathematics 9709 · AS & A Level · Differentiation
Differentiation — practice question
The curve is given by $2x^3 - y^3 - 3xy^2 = 2a^3$, where $a$ is a non-zero constant.
Worked solution & mark scheme
This 9-mark question has a full step-by-step worked solution and mark scheme. One marking point: “State, or make clear, $3y^2\frac{dy}{dx}$ as the derivative of $y^3$” …
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