Mathematics 9709 · AS & A Level · Differentiation

Differentiation — practice question

The curve is described parametrically by $x = 2 \ln (t + 1)$ and $y = 4e^t$.
(main)[6]

Find the equation of the tangent to the curve at the point where $t = 0$. Give your answer in the form $ax + by + c = 0$, with $a$, $b$ and $c$ integers.

Worked solution & mark scheme

This 6-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Obtain $\dfrac{dx}{dt} = \dfrac{2}{t+1}$” …

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