(i)[4]
Show, by differentiation, that $\frac{dy}{dx} = \frac{2x - 4xy}{2x^2 - 3}$.
(ii)[4]
Find the equation of the normal to the curve at the point where $x = 2$, and express your answer in the form $ax + by + c = 0$.
Mathematics 9709 · AS & A Level · Differentiation
Differentiation — practice question
A curve is given by the equation $x^2 - 2x^2y + 3y = 9$.
Worked solution & mark scheme
This 8-mark question has a full step-by-step worked solution and mark scheme. One marking point: “State $3\dfrac{dy}{dx}$ as the derivative obtained from $3y$.” …
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