Mathematics 9709 · AS & A Level · Differentiation

Differentiation — practice question

(i)[4]

Find the value of $\frac{dy}{dx}$ at $x = 4$ for $y = x\ln(x - 3)$.

(ii)[3]

Find the value of $\frac{dy}{dx}$ at $x = 4$ for $y = \frac{x - 1}{x + 1}$.

Worked solution & mark scheme

This 7-mark question has a full step-by-step worked solution and mark scheme. One marking point: Differentiate $\ln(x-3)$ to get $\frac{1}{x-3}$

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