(a(i))[4]
Show that $\frac{dy}{dx} = \frac{6 - 2xy}{x^2 + 2y}$.
(a(ii))[3]
Find the equation of the tangent to the curve at the point with coordinates $(1, 2)$, and give your answer in the form $ax + by + c = 0$.
Mathematics 9709 · AS & A Level · Differentiation
Show that $\frac{dy}{dx} = \frac{6 - 2xy}{x^2 + 2y}$.
Find the equation of the tangent to the curve at the point with coordinates $(1, 2)$, and give your answer in the form $ax + by + c = 0$.
This 7-mark question has a full step-by-step worked solution and mark scheme. One marking point: “State that $2xy+x^2\frac{dy}{dx}$ is the derivative of $x^2y$” …