Mathematics 9709 · AS & A Level · Differentiation

Differentiation — practice question

The diagram represents the curve with parametric equations $x = 1 + \sqrt{t}$, $y = (\ln t + 2)(\ln t - 3)$, for $0 \le t \le 25$. It meets the $x$-axis at the points $A$ and $B$ and has a minimum point $M$.
(a)[4]

Show that it follows that $\dfrac{dy}{dx} = \dfrac{4\ln t - 2}{\sqrt{t}}$.

(b)[2]

Find the exact gradient at $B$ on the curve.

(c)[3]

Find M's exact coordinates.

Worked solution & mark scheme

This 9-mark question has a full step-by-step worked solution and mark scheme. One marking point: Use the product rule to determine $\dfrac{dy}{dt}$

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