(a)[4]
Show that $\frac{dy}{dx} = \frac{x^2 + y^2}{y^2 - 2xy}$.
(b)[5]
Find the coordinates of the points on the curve at which the tangent is parallel to the $y$-axis.
Mathematics 9709 · AS & A Level · Differentiation
Differentiation — practice question
The curve is defined by $x^3 + 3xy^2 - y^3 = 5$.
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This 9-mark question has a full step-by-step worked solution and mark scheme. One marking point: “State or imply $3y^2 + 6xy\,\dfrac{dy}{dx}$ for the derivative of $3xy^2$” …
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