The curve is given by $3x^2 - y^2 - 4\ln(2y + 3) = 26$.
(main)[6]
Find the equation for the tangent to the curve at the point $(3, -1)$.
Worked solution & mark scheme
This 6-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Differentiate $-y^2$ to give $-2y\frac{dy}{dx}$” …
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