(i)[5]
Show that the gradient satisfies $\frac{dy}{dx} = 2\tan t$.
(ii)[2]
Hence determine the $x$-coordinate of the point on the curve where the gradient of the normal is $2$. Give your answer to $3$ significant figures.
Mathematics 9709 · AS & A Level · Differentiation
Differentiation — practice question
For the curve, the parametric equations are $x = 2t + \sin 2t$, $y = 1 - 2\cos 2t$, where $-\frac{1}{2}\pi < t < \frac{1}{2}\pi$.
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