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Solve the differential equation and find the value of $x$ when $y = 2$.
Mathematics 9709 · AS & A Level · Differential equations
Differential equations — practice question
The variables $x$ and $y$ are linked by the differential equation $\frac{dy}{dx} = \frac{y^2 + 4}{x(y + 4)}$ for $x > 0$. It is also stated that $x = 4$ when $y = 2\sqrt{3}$.