(i)[2]
Write $\frac{1}{x(2x + 3)}$ as a partial fraction decomposition.
(ii)[7]
The variables $x$ and $y$ obey the differential equation $x(2x + 3)\frac{dy}{dx} = y$, and it is stated that $y = 1$ when $x = 1$. Solve the differential equation and determine $y$ when $x = 9$, expressing your answer correct to 3 significant figures.