The curve is given by $y = 2x^2 + m(2x + 1)$, where $m$ is constant, and the line is given by $y = 6x + 4$.
(main)[5]
Show that the line crosses the curve at two separate points for every value of $m$.
Worked solution & mark scheme
This 5-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Rearranges to the quadratic $2x^2+m(2x+1)-6x-4=0$” …
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