Mathematics 9709 · AS & A Level · Coordinate geometry

Coordinate geometry — practice question

The vectors $\mathbf{u}$ and $\mathbf{v}$ are given by $\mathbf{u} = \begin{pmatrix} q \\ 2 \\ 6 \end{pmatrix}$ and $\mathbf{v} = \begin{pmatrix} 8 \\ q-1 \\ q^2-7 \end{pmatrix}$, with $q$ as a constant.
(i)[3]

Find the values of $q$ such that $\mathbf{u}$ is perpendicular to $\mathbf{v}$.

(ii)[4]

Find the angle between $\mathbf{u}$ and $\mathbf{v}$ for $q = 0$.

Worked solution & mark scheme

This 7-mark question has a full step-by-step worked solution and mark scheme. One marking point: Form scalar product $\mathbf{u}\cdot\mathbf{v}=8q+2q-2+6q^2-42

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