(a)[3]
Show that $a = \dfrac{27}{2}$ is correct.
(b)[3]
Show that $\text{E}(X) = \dfrac{27}{2} \ln \dfrac{3}{2} - 3$ holds.
Mathematics 9709 · AS & A Level · Continuous random variables
Show that $a = \dfrac{27}{2}$ is correct.
Show that $\text{E}(X) = \dfrac{27}{2} \ln \dfrac{3}{2} - 3$ holds.
This 6-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Tries the integration $\int_2^3\left(a x^{-2}-18x^{-3}\right)dx$” …