(a)[3]
Show that, in fact, $a = \frac{2}{b^2}$.
(b)[6]
Show that, indeed, $\mathrm{P}(X < \mathrm{E}(X)) = \frac{4}{9}$.
Mathematics 9709 · AS & A Level · Continuous random variables
Show that, in fact, $a = \frac{2}{b^2}$.
Show that, indeed, $\mathrm{P}(X < \mathrm{E}(X)) = \frac{4}{9}$.
This 9-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Take the area/integral to equal $1$, for example $\frac12 b\cdot ab=1$ or $a\int_0^b x\,dx=1$” …