The polynomial $p(x)$ is given by $p(x) = 6x^3 + ax^2 + bx - 20$, where $a$ and $b$ are constants. It is stated that $(x + 2)$ is a factor of $p(x)$ and that dividing $p(x)$ by $(x + 1)$ leaves remainder $-11$.
(a)[5]
Determine the values of $a$ and $b$.
(b)[4]
Hence factorise $p(x)$, and find the exact roots of the equation $p(3x) = 0$.
Worked solution & mark scheme
This 9-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Put $x=-2$ into the expression and set it equal to zero” …