Let $p(x)$ represent the polynomial $4x^3 + ax^2 + 9x + 9$, where $a$ is a constant. When $p(x)$ is divided by $(2x - 1)$, the remainder is $10$.
(i)[3]
Determine the value of $a$ and then show that $(x - 3)$ is a factor of $p(x)$.
(ii)[4]
With this value of $a$, solve $p(x) = 0$.
Worked solution & mark scheme
This 7-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Insert $x=-\frac{1}{2}$ and set the result equal to $10$” …