On one diagram, sketch the graphs of $y = |3x + 2a|$ and $y = |3x - 4a|$, where $a$ is a positive constant. State the coordinates of the points at which each graph meets the axes.
(b)[3]
Find the coordinates of the intersection point of the two graphs.
(c)[1]
Deduce the solution of the inequality $|3x + 2a| < |3x - 4a|$.
Worked solution & mark scheme
This 7-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Draw two V-shaped graphs, with one vertex on the negative $x$-axis and the other on the positive $x$-axis” …