The polynomial $2x^3 + ax^2 + bx + 6$, with $a$ and $b$ as constants, is written as $p(x)$. It is stated that dividing $p(x)$ by $(x - 3)$ leaves a remainder of $30$, and dividing $p(x)$ by $(x + 1)$ leaves a remainder of $18$.
(i)[5]
Find the values of $a$ and $b$
(ii)[4]
Using these values of $a$ and $b$, confirm that $(x - 2)$ divides $p(x)$ and then factorise $p(x)$ fully.
Worked solution & mark scheme
This 9-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Substitute $x=3$ and set the result equal to $30$” …